What is the probability that the dealer busts and you may


Blackjack Table

A standard deck of playing cards contains 52 cards divided equally into four suits: Spades, Hearts, Diamonds, and Clubs. Each suit contains thirteen cards: 2, 3, 4, 5, 6, 7, 8, 9, 10, J(ack), Q(ueen), K(ing), A(ce).

You walk up to the blackjack table at your local casino and ask to be dealt in. You are dealt two cards, the 5 of hearts and the 7 of spades. You see that the dealer also has two cards. One is face down, and the other is the 6 of clubs. You decide to let it ride and hope the dealer busts. The dealer's hidden card is revealed to be the 8 of clubs, making the dealer's hand worth 14 points. What is the probability that the dealer busts? You may assume that the dealer is usign only 1 deck, and that you have not observed the values of any other cards.

In blackjack, the worth of the dealer's hand is determined by summing the values of his individual cards. Numbered cards are worth their face value. Jacks, Queens, and Kings are worth 10 points, and Aces are worth either 11 or 1 point (in this question, Aces will always be worth 1 point). The dealer starts with 2 cards and repeats the following strategy:

If the dealer's hand is worth 16 or fewer points he draws another card. The value of the dealer's hand is now the value of his two starting cards, and all the cards that he has subsequently drawn.

When the dealer stops drawing, the value of his hand will be 17 or higher. If it is higher than 21, the dealer is said to have "bust" meaning that his hand is worthless. If it is between 17 and 21 (inclusive) then the dealer's hand is worth its value.

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Basic Statistics: What is the probability that the dealer busts and you may
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