A particle moves along a straight line and its position at time t is given by s(t) = 2t3 - 21t2 + 60t where s is measured in feet and t in seconds.
Find the velocity (in ft/sec) of the particle at time t = 0:
The particle stops moving (i.e. is in a rest) twice, once when t = A and again when t = B where A < B.
What is the position of the particle at time 14?
Ffinally, what is the total distance the particle travels between time 0 and time 14?