What is the path attenuation between transmitter and, Electrical Engineering

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What is the path attenuation between transmitter and

What is the path attenuation between transmitter and receiver at a frequency of 1.2 GHz and a distance of 11,000. Given: f = 1.2GHz d = 11,000 mi. Calculate the path attenuation; dB = 37dB + 20 log f + 20 log d = 37 + 20 log 1.2^9 + 20 log 11,000 (0r would it be, 37 + 20 log 1.2 + 20 log 11,000) = 37 + 181.58 + 80.83 = 299.41 dB

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Electrical Engineering: What is the path attenuation between transmitter and

Reference No:- TGS0586958

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Recent Questions Asked Electrical Engineering

Q : A 4500 ml sample of a 0273 m solution of silver nitrate is

Q : Objects with masses of 180 kg and a 480 kg are separated by

Q : How the attributes of a project team are important in these

Q : Determine the temperature dependence of the diffustion

Q : What is the path attenuation between transmitter and

Q : Describe the importance of project sponsorship and

Q : Define how the futures market helps our economy what risk

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Q : Two resistors of r1 207 and r2 697 are connected in

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Request for Solution File

Ask an Expert for Answer!!

Electrical Engineering: What is the path attenuation between transmitter and

Reference No:- TGS0586958

Recent Questions Asked Electrical Engineering

Q : A 4500 ml sample of a 0273 m solution of silver nitrate is

Q : Objects with masses of 180 kg and a 480 kg are separated by

Q : How the attributes of a project team are important in these

Q : Determine the temperature dependence of the diffustion

Q : What is the path attenuation between transmitter and

Q : Describe the importance of project sponsorship and

Q : Define how the futures market helps our economy what risk

Q : For each of the following bonds indicate the posotive end

Q : Two resistors of r1 207 and r2 697 are connected in

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