You know that 10Mbps Ethernet has a 64-byte minimum frame-size (inc. FCS),and that this is related to the maximum distance possible between two nodes on a shared segment such that collisions can be detected.
This problem looks at choosing a target max-link-distance, and determining the minimum allowed framesize.
You can use speed-of-light-in-vacuum = c = 300,000km/sec,and speed-of-light-in-fiber = 0.6c throughout this homework
assignment.
a. If the 1-way maximum distance is 15km for a fiber link, what is the minimum frame-size (for 10Mbps link-speed)?
b. Generalize the above result- if the 1-way maximum distance is "X"km, develop a formula for the minimum frame-size.
(Hint: your formula should yield about 64Bytes min_frame for 4.6km 1-way-distance, i.e. real Ethernet parameters).