We have an unfair die where any even number is twice as


We have an unfair die where any even number is twice as likely as any odd number. So a, 2, 4, and 6 are all equally likely, and 1, 3, and 5 are all equally likely, but 2 is twice as likely as a 3, and so on. Find the probabilities of all the simple events

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Basic Computer Science: We have an unfair die where any even number is twice as
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