Two cyclists are 729 meters apart at t 0 they both start

Question

Solve the all parts of given problem:

Problem: Two cyclists are 72.9 meters apart. At t = 0, they both start to accelerate toward each other. Both start from rest. Cyclist A has an acceleration of .6 m/s², and cyclist B has an acceleration of -1.2 m/s².

Part I: When do the cyclists meet?

Part II: Which cyclist is moving faster when they meet?

Part III: What is the ratio of the distance traveled by the cyclist A to that traveled by cyclist B?

Please explain each step and equations used for above problem.