To reduce the power requirement of elevator motors


Solve the all parts of given question:

Question: To reduce the power requirement of elevator motors, elevators are counterbalanced with weights connected to the elevator by a cable that runs over a pulley at the top of the elevator shaft. Neglect any effects of friction in the pulley. Assume a 1500 kg elevator that carries a maximum load of 800 kg is counterbalanced with a mass of 1900 kg.

Part I: What is the power provided by the motor when the elevator ascends fully loaded at a speed of 1.6 m/s.

IN kW

Part II: How much power is provided by the motor when the elevator ascends at 1.6 m/s without a load?

In kW

Please show work I think I have the answer just not positive. Thank you.

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Physics: To reduce the power requirement of elevator motors
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