The 0.500 M solutions of Na2CO3 and CaCl2 were prepared ahead of time. The CaCl2 is purchased in the hydrated form; it contains one mole of water for each mole of the compound, Na2CO3 * H2O, and has a formula weight of 124.01 g/mol. To prepare 100 mL of a 0.500 M solution of this hydrated form requires 0.0500 moles of this salt. Calculate the grams of this compound that equals 0.0500 moles, showing all your calculations.