The standard electrode potential for the following reaction


Question - The standard electrode potential for the following reaction is -.57 V. What is the potential at pH = 12?

TeO32- [1M] (aq) + 3H20 (l) + (4e-) ----> Te (s) + 6OH- (aq)

Explicate the each step. Explicate the process and each step.

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Chemistry: The standard electrode potential for the following reaction
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