Repeat Problem 5.7 using the Causebrook correction to find a better value of the excess path loss.
Problem 5.7
A 1 GHz transmitter sends a signal to a receiver 4 km away. There are three knife-edged absorbing screens intercepting the direct path. The first screen has an excess height of 5 m and is 1 km from the transmitter. The second screen has an excess height of 10 m and is 2 km from the transmitter. The third screen has an excess height of 5 m and is 3 km from the transmitter. Find the excess path loss using the Deygout method.