The position of a 9x10-31kg particle is given by xt3t2x4ty, Physics

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The position of a 9x10-31kg particle is given by xt3t2x4ty

The position of a 9x10-31kg particle is given by: x(t)=3t2x+4ty where x and y are unit vectors. What are the particleâ€^TMs velocity and acceleration as a function of time? You can leave them in component form. What is the average velocity between t=1s and t=3s? What is the force acting on the particle?

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Physics: The position of a 9x10-31kg particle is given by xt3t2x4ty

Reference No:- TGS0648201

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Physics: The position of a 9x10-31kg particle is given by xt3t2x4ty

Reference No:- TGS0648201

Recent Questions Asked Physics

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