The position of a 300 object is given in meters by, Physics

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The position of a 300 object is given in meters by

The position of a 300 object is given (in meters) by 5t^3-7.9t^2-45t , where t is in seconds. I need to find:

A) What is the average net power input during the interval from t=0s to t=1.9s?

B) What is the average net power input during the interval from t=1.9s to t=4.1s?

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Physics: The position of a 300 object is given in meters by

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