The force of the expanding gases on a 002 kg bullet is


The force of the expanding gases on a 0.02 kg bullet is given by f=f0-f.1*t . Initially stationary at x=0 , the bullet reaches a speed of 1000 kph by the time it exits the gun. f0 = 7000 N and f1=2.9*106 N/s. a. What is the total linear impulse acting on the bullet? b. When does the bullet exit the gun?

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Civil Engineering: The force of the expanding gases on a 002 kg bullet is
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