Te position of a squirrel running in a park is given by


The position of a squirrel running in a park is given by : r=[(00.280 m/s)t+(0.0360 m/s^2)t^2]i+(0.0190 m/s^3)t^3j. At 4.20 , how far is the squirrel from its initial position?

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Physics: Te position of a squirrel running in a park is given by
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