Te dispersion coefficient of a material is dndwavelength


The dispersion coefficient of a material is dn/dwavelength = 17.1 x 105 nm-1, such that n0 = 1.500 when wavelength= 543.0 nanometer. If theta is the refraction angle, find the absolute value of angular separation of the refracted beams produced by this material to a beam containing wavelengths between wavelength1 = 431.0 nm and wavelength2 = 643.0 nm if its angle of incidence on the material is 53.55 degree?

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Physics: Te dispersion coefficient of a material is dndwavelength
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