Discussion:
Q1) It is believed that 1 in every 10 cases are observed with diarrhoeal disease. To verify the claim, a sample of 10 persons is collected. A test is carried out at alpha=0.05.
a)State the underlying distribution of the problem.
b)Find the probability that at least 7 persons carry the disease.
c)A test is conducted at alpha=0.05. suppose the null hypothesis is rejected if the result in b) is smaller than 0.05. what is the conclusion?
Q2)How to work out p-value?
if; t-test= -4.769, with df=7 therefore t7(0.95)= 1.895, since alpha is=0.05. Ho (null hypothesis) is rejected in t-test since -4.769 falls into
the critical (rejection) region. where ( Ho: m=mo & H1: m not= mo)
is that; p-value= 2*P(T>=-4.769|T~t7)=1.998>0.05