Since a nop instruction is implemented as sll 000 and


Since a nop instruction is implemented as sll $0,$0,0 and register $0 can't be written (i.e., it is read only), can the nop instruction ever take more than 5 cycles to go through our 5-stage MIPS pipeline? Explain your answer.

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Basic Computer Science: Since a nop instruction is implemented as sll 000 and
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