Radius of the equipotential surface


A Geiger tube includes of two elements, a long metal cylindrical shell and a long straight metal wire running down the central axis. Model the tube as if both cylinder and wire are infinitely long. The central wire is positively charged and the external cylinder is negatively charged. The potential difference among the wire and the cylinder is 1.11 kV. Assume the cylinder in the Geiger tube consists an inside diameter of 3.96 cm and the wire has a diameter of 0.498 mm. The cylinder is grounded so its potential is equivalent to zero.

(i) Determine the radius of the equipotential surface which consists of a potential equivalent to 530 V? Is this surface closer to the wire or to the cylinder? (In cm) And the equipotential surface closer to the cylinder or wire?

(ii) Explain how far apart are the equipotential surfaces that encompass potentials of 195 and 245 V? (In mm)

(iii) Compare your outcome in Part (ii) to the distance among the two surfaces which encompass potentials of 690 and 730 V, correspondingly. (In mm)

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Physics: Radius of the equipotential surface
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