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q in newtons ring experiment the diameter of

Q. In Newton's ring experiment, the diameter of certain order of dark ring is measured to be double that of the second ring. What is the order of the ring?

Data : d_n = 2d₂ ; n = ?

d_n² = 4nRλ

d₂² = 8Rλ

d_n² / d₂² = n / 2

( 4d₂² / d₂² ) / ( n / 2)

∴ n = 8.

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