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Prove this by taking vectors a b and c such that c a - b

Question: The law of cosines for a triangle with sides of length a, b, and c, in which the angle opposite the side of length c is C, takes the form

C² = a² + b² - 2ab cos C

Prove this by taking vectors a, b, and c such that c = a - b and considering the dot product c · c = (a - b) · (a - b).

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Mathematics: Prove this by taking vectors a b and c such that c a - b

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Mathematics: Prove this by taking vectors a b and c such that c a - b

Reference No:- TGS02389428

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