Assignment:
If 275.0 mL of 0.5000 M ZnCl2 reacts with 1.650 x 10 to 23rd power of AlPO4 compounds in the following reaction, what is the limiting reagent, how many moles of excess reagent will there be, and how many grams of each product will form?
3 ZnCl2 + 2 AlPO4 yields Zn3(PO4)2 + 2 AlCl3
Provide complete and step by step solution for the question and show calculations and use formulas.