A 2.17 kg particle has the xy coordinates (-1.36 m, 0.792 m), and a 2.34 kg particle has the xy coordinates (0.487 m, -0.102 m). Both lie on a horizontal plane. At what (a)x and (b)y coordinates must you place a 3.34 kg particle such that the center of mass of the three-particle system has the coordinates (-0.449 m, -0.561 m)?