Problem- for the diprotic weak acid h2a ka1 20 times 10-5, Chemistry

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Problem- for the diprotic weak acid h2a ka1 20 times 10-5

Problem- For the diprotic weak acid H2A, Ka1 = 2.0 × 10-5 and Ka2 = 5.0 × 10-7.

Part 1) What is the pH of a 0.0750 M solution of H2A?

Part 2) What are the equilibrium concentrations of H2A and A2- in this solution?

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Chemistry: Problem- for the diprotic weak acid h2a ka1 20 times 10-5

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Chemistry: Problem- for the diprotic weak acid h2a ka1 20 times 10-5

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