Someone has stolen an ATM card and knows that the first and last digits of the (4 digit) PIN are 8 and 1, respectively. He has three tries before the card is retained by the ATM (but does not realize that). So he randomly selects the 2nd and 3rd digits for the first try, then randomly selects a different pair of digits for the second try, and yet another randomly selected pair of digits for the third try. What is the probability that the individual gains access to the account given that he knows all the rules to making a PIN? (PIN cannot be all four identical digits, pin cannot be sequences of consecutive ascending or descending digits such as 6543, and pinn cannot start with 19 (birth years too easy to guess)). The answer says it is .0333 but I have no idea how they got that.