Plot the ASE versus reuse distance D (0 ≤ D ≤ 10) of a TDMA uplink with hexagonal cells of radius R = 1, assuming that all users in the cell are assigned the same fraction of time and the same transmit power and that all users are located on a cell boundary. Your computation should be based on a path loss of γ = 2 and interference from only the first ring of interfering cells, where the interferers have probability 1/5 of being in one of the following five locations: the cell boundary closest to the cell of interest; halfway between the base station and this closest cell boundary; in the cell center; the cell boundary farthest from the cell of interest; or halfway between the base station and this farthest cell boundary. Also plot the ASE and optimal reuse distance for the cases where, with probability 1, the interferers are on the
(a) closest or
(b) farthest cell boundary. Compare the differences in these plots.