Molecular iodine i2g dissociates into iodine atoms at 625 k


Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1.

(a) What is the half-life for this reaction?

(b) If you start with 0.052 M I2 at this temperature, how much will remain after 5.16 s assuming that the iodine atoms do not recombine to form I2?

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Chemistry: Molecular iodine i2g dissociates into iodine atoms at 625 k
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