Moe larry and curly are in a two round truel in round 1


Question: Moe, Larry, and Curly are in a two round truel. In round 1, Larry fires first, then Moe, then Curly. Each stooge gets one shot in round 1. Each stooge can choose to fire at one of the other players, or to deliberately miss by firing in the air. In round 2, all survivors are given a second shot, in the same order of play. Suppose Larry's accuracy is 30%, Moe's is 80%, and Curly's is 100%. For each player, the preferred outcome is to be the only survivor, next is to be one of two survivors, next is the outcome of no deaths, and the worst outcome is that you get killed. Assume an accurate shot results in death of the one shot at. Who should each player shoot at and find the probabilities of survival under the Nash equilibrium.

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