Magnitude of the squirrel velocity


The position of a squirrel running in a park is given by r=[(0.280m/s)t+(0.0360m/s^2)t^2]+(0.0190m/s^3)t^3.

a. At 4.31 , how far is the squirrel from its initial position?

b. At 4.31 , what is the magnitude of the squirrel's velocity?

c. At 4.31 , what is the direction (in degrees counterclockwise from +x-axis) of the squirrel's velocity?

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Physics: Magnitude of the squirrel velocity
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