Magnitude and direction of the weakest electric field


A proton is moving horizontally to the right at 4.20×10^6m/s.

Part A: Find out (i) the magnitude and (ii) direction of the weakest electric field which can bring the proton uniformly to rest over a distance of 3.50 cm.

Part B: Counter clock-wise from the left direction

Part C: Determine how much time does it take the proton to stop after entering the field?

Part D: Determine minimum field ((i) magnitude and (ii) direction) would be required to stop an electron beneath the conditions of part (i)?

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Physics: Magnitude and direction of the weakest electric field
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