In the picture below, a 10 kg bar 1.2 m long is set up to rotate about its center (the dark circle). Each arrow represents a force that is being applied to the bar. FA = 46 N, FB = 47 N, FC = 21 N, & FD = 41 N. FB is applied halfway between the center and the end and FC is applied right at the end. Using the center as the pivot point, answer the following questions.
a.) Determine the net torque on the bar.
m?N
b.) Determine the moment of inertia of the bar.
kg?m2
c.) Determine the angular acceleration of the bar.
rad/s2