Question: Solve the given quadratic equations by finding appropriate square roots as in Example 1.
x2 = 100
Example: Quadratic equation solutions
In solving x2 = 16 we may write x2 - 16 = 0 and complete the solution by factoring. This gives us x = 4 and x = -4. Therefore, the principal square root of 16 and its negative both satisfy the original equation. Thus, we may solve x2 = 16 by equating x to the principal square root of 16 and to its negative. The roots of x2 = 16 are 4 and -4 We may solve (x - 3)2 = 16 in a similar way by equating x - 3 to 4 and to -4.
x - 3 = 4 or x - 3 = -4