In an l-r-c series circuit l 0405h r 310 ohm and c 591, Physics

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In an l-r-c series circuit l 0405h r 310 ohm and c 591

Solver the all parts of given question:

Question: In an L-R-C series circuit, L = 0.405H, R = 310 ohm , and C = 5.91 x 10^-8. When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.498A

Part I: What is the voltage amplitude of the source?

Part II: What is the amplitude of the voltage across the resistor?

Part III: What is the amplitude of the voltage across the inductor?

Part IV: What is the amplitude of the voltage across the capacitor?

Please provide clear step by step solution with notes on concepts and equations being used.

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Physics: In an l-r-c series circuit l 0405h r 310 ohm and c 591

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Physics: In an l-r-c series circuit l 0405h r 310 ohm and c 591

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