In a random sample of 60refrigerators the mean repair cost


In a random sample of 60?refrigerators, the mean repair cost was ?$141.00 and the population standard deviation is ?$16.60.

Construct a 90?% confidence interval for the population mean repair cost. Interpret the results.

Construct a 90?% confidence interval for the population mean repair cost.

90?% confidence interval is __________, __________?

?(Round to two decimal places as? needed.)

Interpret you results. Choose the correct answer below.

A. With 90?% ?confidence, it can be said that the confidence interval contains the true mean repair cost.

B.With 90?% ?confidence, it can be said that the confidence interval contains the sample mean repair cost.

C.The confidence interval contains 90?% of the mean repair costs.

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Basic Statistics: In a random sample of 60refrigerators the mean repair cost
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