If roots of (x-p)(x-q) = c are a and b
what will be the roots of (x-a)(x-b) = -c please explain?
Ans) (x-p)(x-q)=c
x2-(p+q)x-c=0
hence, a+b=p+q
and a.b=pq-c
a.b+c=p.q
by solving other eq we get
x2-(a+b)x+ab+c=0
thus sum of roots=a+b=p+q
product of roots=a.b+c=p.q
hence its roots are pand q