How many ml of the base are required to reach equivalence
65.50 mL of 0.161 M HF is titrated with 0.1200 M NaOH. How many mL of the base are required to reach the equivalence point? (Ka for HF is 6.8 x 10-4)
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65.50 mL of 0.161 M HF is titrated with 0.1200 M NaOH. What is the pH at the equivalence point? (Ka for HF is 6.8 x 10-4)
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