How many liters of 0150 m ki would be required to react
How many liters of 0.150 M kI would be required to react completely with 15.00 grams of lead (II) nitrate?
Pb(NO3)2(aq) + 2KI (aq) -> PbI2(s) + 2KNO3(aq)
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how many liters of 0150 m ki would be required to react completely with 1500 grams of lead ii nitratepbno32aq 2ki aq
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