How high will the ball above ground after one second


Assume you throw the baseball straight up at the velocity of 32 feet per second. The function can be created by stating distance above ground, s, as the function of time, t. This function is s = -16t2 + v0t + s0

• 16 represents ½g, gravitational pull due to gravity (estimated in feet per second 2).
• v0 is initial velocity (how hard do you throw object, estimated in feet per second).
• s0 is initial distance above ground (in feet). If you are standing on ground, then s0 = 0.
a) Find function which describes the problem?

b) Ball will be how high above ground after one second?

c) How long will it take to hit ground?

d) Find maximum height of ball?

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Mathematics: How high will the ball above ground after one second
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