Given g 667259 times 1011 nm2kg2 a small moon of a planet


Given: G = 6.67259 × 10?11 Nm2/kg2 A small Moon of a planet has an orbital period of 0.714 days and an orbital radius of 3.63 × 105 km. From these data, determine the mass of the planet. Answer in units of kg

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Physics: Given g 667259 times 1011 nm2kg2 a small moon of a planet
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