32 bit computer
32 bit instruction: 2 fields:opcode field and immediate operand or operand address
opcode = 1 byte wide
express ans in powers of 2
1.give number of available unique instructions
2.give max indrectly addressable mem capacity in bytes.
3.give max directly addressable memory capacity in bytes.
4 give bits needed for the program counter and instruction register.
5 max value of an unsigned data operand.
Please show how you got the answers.