find the sum of all 3 digit numbers which leave


Find the sum of all 3 digit numbers which leave remainder 3 when divided by 5.

Ans:    103, 108..........998

 

a + (n-1)d

=

998

103 + (n-1)5

=

998

n

=

180

S180  = 180/2 [103 + 998]

= 90 x 1101

S180 =    99090

 

Request for Solution File

Ask an Expert for Answer!!
Mathematics: find the sum of all 3 digit numbers which leave
Reference No:- TGS0263466

Expected delivery within 24 Hours