A team of astronomers have proposed Io construct a large parabolic telescope mirror by spinning a cylindrical container of mercury (rho = 13,500 kg m-3). The dish would be 10 m in diameter and spin at an angular velocity of 0.5 rad s-1. What is the minimum volume of mercury needed to prevent the base of the container from being exposed during operation? Assume that the container has a flat bottom and vertical sidewalls, and the liquid is in solid-body rotation. Answer hint; Volume = 12.5 m3, fluid height = 0.319 m at the side walls The telescope mirror design was approved, and a container must be sized to support the load of the spinning mercury. What is the tension force in the container side-walls assuming that it supports all the pressure acting on the side-walls?