Find mean-variance-standard deviation


Discuss the below:

Q: a) Compute Ex, Ex^2, Ey, Ey^2

Ex=103

Ex^2=3241(11)^2+(36)^2.....)

Ey=90

Ey^2=2024

x: 11    0     36    21    31    23    24    -11    -11    -21

y: 10    -2    29    14    22    18    14    -2      -3     -10

b) Find mean, variance, standard deviation.

For x: (mean) I add all numbers and divide by 10

So x= Ex/10=10.03

So y=Ey/10=9

For the sample variance For standard deviation

The denominator is n-1=9 s^2 = { Ex^2 - [(Ex)^2 / n] } / n-1 s^2 = { Ex^2 - [(Ex)^2 / n] } / n-1

s^2 = { 3241 - [(103)^2 / 10] } / 10-1 s^2 = { 2024 - [(90)^2 / 10] } / 10-1
s^2 = { 3241 - [10609/ 10] } / 9 s^2 = { 2024 - [8100/ 10] } / 9
s^2 = { 3241 - [1060.9] } / 9 s^2 = { 2024 - 810] } / 9
s^2 = { 2180.1 } / 9=242.2333 which=15.56 s^2 = 1214 / 9=134.88=11.61

c) compute 75% chebyshev interval around the mean of x and y values. Use the intervals to compare two funds.

d) Compute the coefficient of variation of each fund. If s represents risks and the x(mean) represents expected return, then s√x can be the measure of risk per unit of expected return. Why is the smaller cv better?

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Basic Statistics: Find mean-variance-standard deviation
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