Find magnitude of the acceleration of the particle at theta
The position of a particle moving in a curvilinear path is given by theta=cos2t where theta units are radians and t units are s. The radius of the curvilinear path is 4 in. What is the magnitude of the acceleration of the particle at theta = 40°?
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The radius of the curvilinear path is 4 in. What is the magnitude of the acceleration of the particle at theta = 40°?
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calculate the following (a) the work done by this force on the particle J (b) the change in the potential energy of the system J (c) the kinetic energy the particle has at x = 4.90 m if its speed is 3.00 m/s at x = 0.96 m J
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