Figure shows the second derivative of hx for -2 x 1 if


Question: Figure shows the second derivative of h(x) for -2 ≤ x ≤ 1. If h'(-1) = 0 and h(-1) = 2,

(a) Explain why h'(x) is never negative on this interval.

(b) Explain why h(x) has a global maximum at x = 1.

(c) Sketch a possible graph of h(x) for -2 ≤ x ≤ 1.

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Mathematics: Figure shows the second derivative of hx for -2 x 1 if
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