Explain what was the percentage by mass


A 0.2527-g sample of a mixture of Mg(OH)2 and Al(OH)3 was treated with 50.00 mL of 0.225 mol L 1 HCl(aq). The resulting solution required 13.73 mL of 0.176 mol L 1 NaOH(aq) to neutralize the excess, unreacted HCl.

What was the percentage by mass of Mg(OH)2 in the original sample? [Hint: When Mg(OH)2 or Al(OH)3 reacts with HCl(aq), the products are a chloride salt, water and CO2(g). Assume that all of the CO2(g) leaves the solution without reacting.]

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Chemistry: Explain what was the percentage by mass
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