The amount of lactic acid,HC3H5O3, produced in a sample of muscle tissue was analyzed by reaction with hydroxide ion.Hydroxide ion was produced in the sample mixture by electrolysis.The cathode reaction is given below.2 H2O(l) + 2 e ‾→ H2(g) + 2 OH ‾ (aq)Hydroxide ion reacts with lactic acid as soon as it is produced.The endpoint of the reaction is detected with an acid-baseindicator. It required 116 s for a currentof 17.4 mA to reach the endpoint. How many grams of lactic acid (a monoprotic acid) were present in thesample?