Example:
Convert the following reduced bearings into whole circle bearings:
(i) N 65° E
(ii) S 43° 15′ E
(iii) S 52° 30′ W
(iv) N 32° 42′ W
Solution: Assume 'θ' be whole circle bearing.
(i) Since it is in NE quadrant,
θ = α = 65° Ans.
(ii) Since it is in south east quadrant
43° 15′ = 180° - θ
or θ = 180° - 43° 15′ = 136° 45′ Ans.
(iii) Since it is in SW quadrant
52° 30′ = θ - 180°
or θ = 180° + 52° 30′ = 232° 30′ Ans.
(iv) Since it is in NW quadrant,
32° 42′ = 360° - θ
Or θ = 360° - 32° 42′ = 327° 18′ Ans.