Evaluate eax cos bx dx by modifying the method in part a


Question: Integrating eax sin bx by parts twice gives

∫eax sinbx dx = eax(A sin bx + B cos bx) + C

(a) Find the constants A and B in terms of a and b. [Hint: Don't actually perform the integration.]

(b) Evaluate ∫ eax cos bx dx by modifying the method in part (a). [Again, do not perform the integration.]

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Mathematics: Evaluate eax cos bx dx by modifying the method in part a
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