Estimate the mean weight for entire population of homes


Discuss the below:

Q: Give an estimate of the sample size needed to obtain the specified margin of error for a 95% confidence interval.

Margin of error = 0.01, standard deviation = 0.25

Scenario: Researchers want to determine the mean number of hours students spend watching TV. A margin of error of 0.25 hour is desired. Past studies suggest a population standard deviation of 1.7 hours is reasonable. Estimate the minimum sample size required to estimate the population mean.

Scenario: Based on a sample of 62 homes, the data offered gives the mean weight in pounds and the standard deviation for paper, glass & plastic. For each category, estimate the mean weight for the entire population of homes. Give the 95% confidence interval.

Sample Mean Sample Standard Deviation
Paper 9.42 4.12
Glass 3.75 3.11
Plastic 1.91 1.07

Solution Preview :

Prepared by a verified Expert
Basic Statistics: Estimate the mean weight for entire population of homes
Reference No:- TGS01911597

Now Priced at $20 (50% Discount)

Recommended (95%)

Rated (4.7/5)