Equation for the tangent line to the graph


Complete the following:

Q1. f(x) = (x + 4)^1/2. An equation for the tangent line to the graph of f(x) at the point where x = 77 would be

x - 6y + 13 = 0
x - 8y + 20 = 0
x - 10y + 29 = 0
x - 12y + 40 = 0
x - 14y + 53 = 0
x - 16y + 68 = 0
none of these

Q2. If f(x) = (x + 2 ln x)^2 , then f '(x) =

(2/x)(x + 1)(x + ln x)
(2/x)(1 + ln x)
(2/x)(x + 2)(x + 2 ln x)
(2/x)(x + 2 ln x)
(4/x)(1 + 2 ln x)
(4/x)(x + 2)(x + 2 ln x)
none of these

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Mathematics: Equation for the tangent line to the graph
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